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x^2-2x=5.0625
We move all terms to the left:
x^2-2x-(5.0625)=0
We add all the numbers together, and all the variables
x^2-2x-5.0625=0
a = 1; b = -2; c = -5.0625;
Δ = b2-4ac
Δ = -22-4·1·(-5.0625)
Δ = 24.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{24.25}}{2*1}=\frac{2-\sqrt{24.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{24.25}}{2*1}=\frac{2+\sqrt{24.25}}{2} $
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